For the following find the real zeros of f Use the real zero
Solution
f(x) = x^3 +3x^2- 13x -15
To find zeros for polynomials of degree 3 or higher we use Rational Root Test.
The Rational Root Theorem tells you that if the polynomial has a rational zero then it must be a fraction pq, where p is a factor of the trailing constant and q is a factor of the leading coefficient.
The factor of the leading coefficient (1) is 1 .The factors of the constant term (-15) are 1 3 5 15 . Then the Rational Roots Tests yields the following possible solutions:
±11, ±31, ±51, ±151
Substitute the psossible roots one by one into the polynomial to find the actual roots.
P(x), we obtain P(1)=0.
Divide P(x) with x+1: (x^3 +3x^2- 13x -15) /(x+1) =x2+2x15
splve the quadratice: x^2 +2x -15 =0
x^2 +5x -3x -15=0
x(x+5)-3(x+5) =0
(x-3)(x+5)
Roots of f(x) are :x =-1, 3, -5
Factored form : (x+1)(x-3)(x+5)
