Suppose that it is known that for all areas in England the p

Suppose that it is known that for all areas in England, the population mean percentage of

Solution

For sample size 32,

Sample mean = 28.83%

Std deviation for sample = std dev for population / rtn = 3.13/rt 32

= 0.5533

Hence distribution of sample mean is approximately normal with N(28.83, 0.5533)