If fx log3 x 1 what is f12 a1 b8 c10 d27Solutionfx log3x1
If f(x) = log3 (x + 1), what is f1(2)?
a)1
b)8
c)10
d)27
Solution
f(x) = log_3(x+1)
1st we will find its inverse for this we will write in exponent form
put y=f(x)
y=log_3(x+1)
3^y=x+1
now we will find its inverse
exchange x to y and y to x
3^x=y+1
y= 3^x-1
f^-1(x)= 3^x -1
put x= 2
f^-1(2) = 3^2-1
=9-1 = 8 answer
