Genotypic Cauat 35 Vial 8M 13L14 1527 31 14 18 35 21 19 2416

Genotypic Cauat- 35 Vial 8M 13L14 15,27 31 14, 18 \'35 21, 19 24.-16,3 ISI Doni nont-ead-Asecasvee-Sapa Se (cisive Allele ta anca is Ro- wen enotiac YaqueKw is R,A- rr VV teetroguency-is a 2-7-54 g, 8-1 7 F

Solution

Total redeye individuals are 293 and sepia eye individuals are 53 from this table

According to hardy weinberg equation allelic frequencies are p and q, so total no. Of individual counted is 293+53= 346

So, the recessive individuals are 53, here 53/346 = .153

p denotes a dominant allele whereas q denotes the recessive allele. Here, q2 is .153

So, q= .39 and p+q = 1

So, p+ .39= 1

p = .61

Allele frequency R (p)= .61 and r(q) = .39

The expected genotypic frequencies. Well, RR (p2) = (.61)2= .372

rr (q2) = .153

Rr (2pq) = 2*p*q = 2* .39*.61= .475

Phenotypic frequencies. Red phenotype = RR + Rr

= .372+.475 = .847

Sapia eye = rr = .153