Sketch and label homologous chromosomes sister chromatids an

Sketch and label (homologous chromosomes, sister chromatids, and each allele) the chromosomes of the following conditions and stages: n = 2: metaphase of mitosis; +/A +/b n = 3; metaphase 1 of meiosis; D/D +/e +/F n = 2; metaphase 2 of meiosis; +/Y +/g Note that the \"Y\" in this case represents the Y sex chromosome n = 2; prophase of mitosis; A +/+ b How many gamete genotypes types would result from the following genotypes: AaBbcc (all traits unlinked) +/A b/b +/c D/D +/E +B/A+ A + +/g +I/h+

Solution

3.

a). Genotype = AaBbcc

The gamete genotype = Aa = 2 types

Bb = 2 varieties and cc = 1 type of gametes

Now just multiply all the types inorder to get the possible genotype gametes for the above genotype

= 2 X 2 X 1

Therefore possible gametes = 4 gametes

b) + & A = 2,

b & b = 1,

+ & c = 2,

D & D = 1,

+ & E = 2

Therefore possible gametes = 2 X 1 X 2 X 1 X 2 = 8 gametes

c) + & A = 2 gametes

B & + = 2

Therefore possible gametes = 2 X 2 = 4 gametes

d) + & g = 2

+ & h = 2

I & + = 2

Therefore the possible gametes = 2 X 2 X 2 = 8 gametes