If the slider block A is moving downward at VA 12 ms Velocit

If the slider block A is moving downward at V_A= 12 m/s Velocity of block B V_B at the instant shown Angular velocity of AB bar omega_AB at the instant shown

Solution

Solution:

For links velocity will act tangentail to link about Instantaneous centre that is D.

Link AD is rotating about D with velocity

Va = 12 m/s

Va = w (AD)

wa= Va/(AD)

= 12/0.3

= 40 rad/s

Link BD will rotate about D (I centre) with same angular velocity

Vb = w(BD)

= 40 (0.25)

= 10 m/s

Angular velocity will act in opp direction, therefore resultant angular for AB is given by

wab = wa + wb

= w + w

= 40 + 40

= 80 rad/s