In one particular population 4 of the individuals cannot rol

In one particular population, 4% of the individuals cannot roll their tongues.
A. what is the frequency of the r allele?
B. what is the frequency of the R allele?
C. what proportion of the population is heterozygous for tongue-rolling?

Solution

Answer:

Let’s assume that individuals cannot roll their tongues is a recessive trait.

Given q=4%,

p will be =96%

Since p+q=1

p=0.96, q=0.04

Hardy weinberg equation

p^2 +2pq+q^2=1

p^2 = number of homozygous dominants

q^2=number of homozygous recessive

2pq=number of heterozygotes

p^2=0.96 x 0.96 = 0.92

q^2 = 0.04 x 0.04 =0.0016

2pq= 2 x 0.96 x 0.04 = 0.077

p^2 = number of homozygous dominants =92%

q^2=number of homozygous recessive =0.01%

2pq=number of heterozygotes=7.7%