The circuit below contains 2 real batteries each having sign

The circuit below contains 2 real batteries, each having significant internal resistance. The potential difference across the terminals of battery # 1, from point \"a\" to point \"b\" equals 1.50 V. 3.00 V. 2.50 V. 3.50 V. 4.50 V. The potential difference across the terminals of battery #2, from point \"a\" to point \"c\" equals 5.00 V. 6.00 V. 3.00 V. 9.00 V. 7.00 V. The conventional current in the 3.00 ohm resistor is equal to zero. is directed from point V to point \"c\". is directed from point \"c\" to point \"d\".

Solution

since batteries have same alignmenet so they will add up.

If I is current through them them

9= I*(r1+r2+R) so I=1.5 A

21) potential difference between a and b is 3 -1.5 *1 = 1,5 V

22) Potential difference between a and c is 6+2*1.5 = 9 V.

23)it would be from c to d