Find the binary representation of x 103 Find the floatingpo
Solution
Solution: Given decimal number is x= 10/3= 3.333
Now
3/2 quotient =1 remainder = 1
1/2 quotient =0 remainder = 1
Here integer part 3 is equivalent to 112
So 310 = 112
Also
0.333x2 product = 0.666 integer part = 0
0.666x2 product = 1.332 integer part = 1
0.332x2 product = 0.664 integer part = 0
0.664x2 product = 0.664 integer part = 0
0.664x2 product = 1.328 integer part = 1
0.328x2 product = 0.656 integer part = 0
0.656x2 product = 1.312 integer part = 1
So 0.33310 =0.01001012
So 3.33310 = 11.01001012
Floating point representation:
Here decimal number is x= 10/3= 3.333=2x1.666
Now 110 = 12 and 0.66610 = 0.1001012 (from above)
So 1.66610= (1.1001012 )x21
Hence floating representation is
The presence of the factor 2E is inconvenient, and so the relative
rounding error associated with x is defined to be
\\delta = (round(x)/x - 1)
=\\frac{round(x)}{x} - 1 = \\frac{round(x) -x}{x} =
| 0 | E = 1 | 1.10010100 |
