A researcher wishes to estimate the percentage of adults who
Solution
a) p = 22% = 0.22
Std error = sqrt[p *(1-p)/n] = sqrt[0.22 * (1-0.22)/n] = sqrt[0.1716/n]
Margin of error = +4% = +0.04
alpha = 1 - 0.95 = 0.05
Critical probability = 1 - alpha/2 = 0.975
Critical value for cumulative probability 0.975 is +1.96
Critical value for 95% confidence is +1.96
Margin of Error = Critical value * Std Error
0.04 = 1.96 * sqrt(0.1716/n)
n = 412.011
Thus n = 412
b) No prior estimates implies p = 0.5
Std error = sqrt[p *(1-p)/n] = sqrt[0.5 * (1-0.5)/n] = sqrt[0.25/n]
Margin of error = +4% = +0.04
alpha = 1 - 0.95 = 0.05
Critical probability = 1 - alpha/2 = 0.975
Critical value for cumulative probability 0.975 is +1.96
Critical value for 95% confidence is +1.96
Margin of Error = Critical value * Std Error
0.04 = 1.96 * sqrt(0.25/n)
n = 600.25
Thus n = 600
