Q3 The intracellular osmolarity is 300 mOsM Which of the fol

Q3: The intracellular osmolarity is ~300 mOsM. Which of the following solutions could be solution A? Hint: Glucose is permeable. a) 300 mM NaCl b) 150 mM NaCl + 150 mM glucose c) 150 mM NaCl d) 100 mM NaCl + 200 mM glucose e) 300 mM glucose

Q4: Which one could be solution B? Briefly explain your answer.

Tonicity Q3: The intracellular osmolarity is 300 mOsM. Which of the following solutions could be solution A? Hint: Glucose is permeable. a) 300 m M NaCl b) 150 mM NaCl 150 mM glucose c) 150 mM NaCl d) 100 mM NaCl 200 mM glucose e) 300 mM glucose Q4: Which one could be solution B? Briefly explain your answer Time

Solution

Q. 3. Answer

300mM NaCl, this will create a tonicity of 2x300=600 mOsM

so the ECF will be hypertonic compared to ICF so cell volume will decrease, but after some time the volume will be constant when it will reach isotonic condition (@ 450 mOsM).

Q. 4. Answer

150 M NaCl + 150 M glucose , which will create osmolarity of 450 mOsM (150x2 + 150 = 450)

but this time, first cell volume will decrease and then increase. due to the permeability of glucose into the cell.