Suppose that Y has an Fdistribution with v130 numerator degr

Suppose that Y has an F-distribution with v1=30 numerator degress of freedom and v2=40 denominator degrees of freedom. Find constants a and b such that P(a < Y < b)= .95

Solution

If the middle area is 0.95, then the right tailed area is (1-0.95)/2 = 0.025.

Thus, using a table/technology, with v1 = 30, v2 = 40,

b = 1.942916 [ANSWER]

By symmetry, a = 1/b, so

a = 0.51469029 [ANSWER]