MUST SHOW WORK TO GET CREDIT 48 Given the following complete

*MUST SHOW WORK TO GET CREDIT*

48. Given the following, complete the ANOVA table and make the correct inference. a) In the above ANOVA table, is the factor significant at 5% level of significant? b) What is the number of observations?

Solution

Source

SS

Df

MS

F

Treatment

2*24.9= 49.8

2

24.9

24.9/0.8481 = 29.3581

Error

22.9

27

22.9/27= 0.8481

Total

49.8+22.9= 72.7

29

Table value of F with DF 2 and 27= 3.35

Calculated F=29.3581 > 3.35 table value

Reject the null hypothesis.

The facter is significant at 5% level.

Number of observations = total DF +1 = 29+1 = 30

Source	SS	Df	MS	F
Treatment	2*24.9= 49.8	2	24.9	24.9/0.8481 = 29.3581
Error	22.9	27	22.9/27= 0.8481
Total	49.8+22.9= 72.7	29