Homework SourseFor each force calculate the z component of the torque due t
For each force, calculate the z component of the torque due to that force, relative to location A (x to the right, y up, z out of the page). Make sure you give the correct sign.
b) Relative to location A, what is the z component of the net torque acting on this object?
| z, (1) | = | __ N · m |
| z, (2) | = | __ N · m |
| z, (3) | = | __ N · m |
| z, (4) | = | __ N · m |
| z, (5) | = | __ N · m |
| z, (6) | = | __ N · m |
| z, at distance d | = | __ N · m |
Solution
direction of the force is parallel to the z-axis as given in the figure. the corss product is 0 Sin(0) =0
torque is CW
Net torque on the body about A = 609 -1392*3 = -3567 N-m
| tz | Perpedicular distance | torque | notes | |
| Tz(1) | 7 m | =+87*7 =609 | ||
| Tz(2) | 0 | 0 | The force passes through the point A | |
| Tz(3) | 0 | 0 | Force passes through point A | |
| Tz(4) | 16 | =-87*16 = -1392 | The torque is CW and given -ve sign | |
| Tz(5) | 16 | =-87*16 = -1392 | torque is CW direction | |
| Tz(6) | 16 | =-87*16 = -1392 | torque is CW | |
| tz(d) | 12 | =-87*0 = 0 | direction of the force is parallel to the z-axis as given in the figure. the corss product is 0 Sin(0) =0 torque is CW |
