Assume f has period 2pi Sketch the graph of f in the interva

Assume f has period 2pi. Sketch the graph of f in the interval [-4pi,4pi].

Is this function an even function? Explain.

Is this function an odd function? Explain

3 3

let theta theta = t

from the graph y = f(t) = 3 + 2sin(t)

f(-t) = 3 + 2sin(-t) = 3 - 2sint

therefore f(t) not equal to f(-t)

then f(t) is odd function