Solve for Io in the following circuit using Source Transform

Solve for I_o in the following circuit using Source Transformation. Keep transforming until you are left with only a Norton equivalent circuit and the load resistor R_L (at least two transforms are required).

Solution

here from the circuit current source, two 8kohms resistorrs and 6 ohm+30 ohmss are parallel

req=(8*8)/(8+8)=4 ohms.

now currrent source, 4ohms and 36 ohms are parallel.

from currrent divission formula

io=(10*4)/(4+6+30)=1 amps.