Homework SourseThe following probability distribution table has been obtain
The following probability distribution table has been obtained for the number of customer arrivals during any given minute at a Beta Alpha supermarket. PLEASE show all your work. I am not that bright in statistics so I need to know exactly where the answer was derived. Thank you for your time and patience.
Solution
The mean is the summation of x*P(x)=0+.2+.6+.3+.8=1.9
The variance of the data is the summation of the weighted square deviation=1.89
The standard deviation of the data is square root of the variance =(1.89)^(1/2)=1.374
| Number of arrivals(x) | Probability(P(x)) | Weighted value(x*P(x)) | Deviation(x-sum of xP(x))^2 | Weighted Square deviation[P(x)*(x-sum of xP(x))^2] |
| 0 | .2 | 0 | 3.61 | .722 |
| 1 | .2 | .2 | .81 | .162 |
| 2 | .3 | .6 | .01 | .003 |
| 3 | .1 | .3 | 1.21 | .121 |
| 4 | .2 | .8 | 4.41 | .882 |
| Total | 1 | 1.9 | 10.05 | 1.89 |
