x 4 line V nt Solutiony 5x4 05x2y 0 Slope ba 15 2 Equ

(x + 4) line V = nt

y = .5(x+4)

0.5x+2-y = 0

Slope = -b/a = -(-1)/.5 = 2

Equation parallel to this is :

y-y\' = M(x-x\')

y-3 = 2(x-4)

y-3 =2x-8

y-2x+5=0

So, equation parallel to this equation is y-2x+5=0, and this passes through y= .5(x+4)

$(x + 4) line V = nt Solutiony = .5(x+4) 0.5x+2-y = 0 Slope = -b/a = -(-1)/.5 = 2 Equation parallel to this is : y-y\' = M(x-x\') y-3 = 2(x-4) y-3 =2x-8 y-2x+5=$

x 4 line V nt Solutiony 5x4 05x2y 0 Slope ba 15 2 Equ

Solution

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