A species of bats is being studied A sample of 40 bats has s
Solution
Formulating the null and alternative hypotheses,
Ho: u >= 5.55
Ha: u < 5.55
As we can see, this is a left tailed test.
Thus, getting the critical z, as alpha = 0.01 ,
alpha = 0.01
zcrit = - 2.326347874
Getting the test statistic, as
X = sample mean = 4.75
uo = hypothesized mean = 5.55
n = sample size = 40
s = standard deviation = 0.7
Thus, z = (X - uo) * sqrt(n) / s = -7.228063223
Also, the p value is
p = 2.44965*10^-13
As |z| > 2.326, and P < 0.01, we REJECT THE NULL HYPOTHESIS.
Thus, there is significant evidence that the mean weight of the bats is less than 5.55 gm at 0.01 level. [CONCLUSION]
