Use the following partially complete Minitab output to answe

Use the following partially complete Minitab output to answer the following questions.

Predictor

Coeff

Se Coef

T

P

Constant

0.9798

0.3367

?

0.011

X

-8.3088

?

-14.54

?

S = ?                R-sq = 93.8%               R-Sq(adj) = ?

            ANOVA:

Source

DF

SS

MS

F

Regression

1

84.106

?

?

Residual Error

14

5.59

?

Total

15

?

Find all of the missing values

Find the estimate of ²

Test for significance of regression. Test for significance of ₁.Comment on the two results. Use = 0.05

Construct a 95% CI on ₁. Use this CI to test for significance of regression.

Comment on results found in parts (c) and (d).

Write the regression model and use it to compute the residual when x= 0.58 and y = -3.30.

Use the regression model to compute the mean and predicted future response when x = 0.6. Given that and S_xx = 1.218, construct a 95% PI on the future response. Which interval is wider? Why?

Predictor	Coeff	Se Coef	T	P
Constant	0.9798	0.3367	?	0.011
X	-8.3088	?	-14.54	?

Solution

Find all of the missing values:

n-1=15=>n=16

df=n-2=16-2=14

for p-value, use excel command =TDIST(14.54,14,2).

This gives p-value=0.000

Predictor

Coeff

Se Coef

T

P

Constant

0.9798

0.3367

0.9798/0.3367=2.91

0.011

X

-8.3088

-8.3088/-14.54=0.5714

-14.54

0.000

S = sqrt(MSE) = sqrt(0.399)=0.632          R-sq = 93.8%        R-Sq(adj) = [(89.696/15)-0.399]/(89.696/15)=0.933

            ANOVA:

Source

DF

SS

MS

F

Regression

1

84.106

84.106/1=84.106

84.106/0.399=210.79

Residual Error

14

5.59

5.59/14=0.399

Total

n-1=15

89.696

Find the estimate of ²

s²=(0.632)²=0.399424

Predictor	Coeff	Se Coef	T	P
Constant	0.9798	0.3367	0.9798/0.3367=2.91	0.011
X	-8.3088	-8.3088/-14.54=0.5714	-14.54	0.000