We are conducting a pou to estimate what fraction of the stu

We are conducting a pou to estimate what fraction of the student population at Rutgers approves of the recently-unveiled master plan2. This problem is about deciding how many people to pou and evaluating how accurate our results are likely to be. We work with the following simplifying assumptions: Everyone on campus has an opinion that is either \'\'Approve\'\' or \'\'Don\'t Approve.\'\' There are no undecided people, and there are no other answers allowed. Some fraction p (0

Solution

AS there are two outcomes, approve or not approve and all trials are independent x follows a Binomial.

E(x) = np

Var(x) = npq = np(1-p)

where n is the no of persons in the campus surveyed

p = prob for saying approved

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As p approximates to x/n,

Let x/n be y

Then |y-p||>=0.5 where y approximates to p.

Thus P(|y-p|>=0.05)<=0.05