In a poll of 1000 adults in July 2010 510 of those polled sa

In a poll of 1000 adults in July 2010, 510 of those polled said that schools should ban sugary snacks and soft drinks. Complete parts a and b below a. Do a majority of adults (more than 50%) support a ban on sugary snacks and soft drinks? Perform a hypothesis test using a significance level of 0.05 State the null and alternative hypotheses. Note that p is defined as the p of people who believe that schools should ban sugary foods n proportion A Ho p0.51 Op. Ho:p=0.50 H,: p #0.50 OA Ho: p

Solution

Set Up Hypothesis
Under The Null Hypothesis H0:P=0.5
Under The Alternate Hypothesis H1: P>0.5
Test Statistic
No. Of Success chances Observed (x)=510
Number of objects in a sample provided(n)=1000
No. Of Success Rate ( P )= x/n = 0.51
Success Probability ( Po )=0.5
Failure Probability ( Qo) = 0.5
we use Test Statistic (Z) for Single Proportion = P-Po/Sqrt(PoQo/n)
Zo=0.51-0.5/(Sqrt(0.25)/1000)
Zo =0.63
| Zo | =0.63
Critical Value
The Value of |Z | at LOS 0.05% is 1.64
We got |Zo| =0.632 & | Z | =1.64
Make Decision
Hence Value of |Zo | < | Z | and Here we Do not Reject Ho
P-Value: Right Tail - Ha : ( P > 0.63246 ) = 0.26354
Hence Value of P0.05 < 0.26354,Here We Do not Reject Ho

ANS)
H0:P=0.5
H1: P>0.5

Zo =0.63

Right Tail - Ha : ( P > 0.63246 ) = 0.264

Do not Reject Ho

Option A