Suppose X follow an exponential distribution with mean 10 de

Suppose X follow an exponential distribution with mean 10, determine a) E(10x-5) and b) the 95th percentile,

Use probability density function
Suppose X follow an exponential distribution with mean 10, determine a) E(10x-5) and b) the 95th percentile,

Use probability density function

Use probability density function

Solution

a)

As

E(x) = 10

then

E(10x - 5) = 10E(x) - 5 = 10(10) - 5

E(10x - 5) = 95 [ANSWER]

********************

b)

Here, the cumulative density function is

F(x) = 1 - exp(-x/10)

Thus, if F(x) = 0.95, finding x,

F(x) = 1 - exp(-x/10)

0.95 = 1 - exp(-x/10)

0.05 = exp(-x/10)

x = -10* ln(0.05) = 29.95732274 [ANSWER, 95TH PERCENTILE]

 Suppose X follow an exponential distribution with mean 10, determine a) E(10x-5) and b) the 95th percentile, Use probability density function Suppose X follow

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site