Solve the equation a 4 cos x 1 2 cos x b4 tan2 x 1 tan2

\"Solve\" the equation - a) 4 cos x + 1 + 2 cos x b)4 tan^2 x - 1 = tan^2 x

a) incomplete

b) 4tan^2x -1 = tan^2x

4tan^2x - tan^2x = 1

3tan^2x = 1

tanx = + /-1/sqrt3

Since interval for angle x over which solution is needed is not given i would

give general solution:

tanx = 1/sqrt3

x = pi/6 +n*pi where n is integer

for tanx = -1/sqrt3

x = pi-pi/6 + n*pi

= 5pi/6 + n*pi where n is integer

Solution : x = pi/6 +n*pi , 5pi/6 +n*pi

substitute n= 0, 1 , 2 ----- to get the values