Ex 343 Assume that X s normally distributed with a mean of 3

(Ex. 3-43) Assume that X s normally distributed with a mean of 37 and a standard deviation of 2. Determine the following. (a) P(X 30) (c) P(33

Solution

(a)P(X<31) =0.0002326

(b) P(X>30) =0.9997674

(c)P(33<X<37) = 0.2857879

(d) P(32<X<39) = 0.6852523

(e) P(30<X<38) = 0.4997674