A 200 L tank contains saturated water at 200 kPa A quarter o

A 200 L tank contains saturated water at 200 kPa. A quarter of the tank is occupied by the liquid water. Determine the total mass of the water (liquid + vapor) in the tank.

Solution

Solution:

Volume of tank = 200 L

volume of water = 1/4 *200 = 50 L = 0.050 m^3

Volume of vapour = 3/4 * 200 = 150 L = 0.150 m^3

now properties of saturated water at 200 KPa:

Specific volume of saturated steam = 0.885735 m^3/kg, therefore specific mass = 1/ 0.885735 kg/m^3

now mass of steam for 0.150 m^3 steam = 0.150/.885735 = .169350 kg

specific volume of saturated water at 200 KPa = 0.00106052 m^3/kg, therefore specific mass = 1/0.00106052 kg/m^3

now mass of 50 L water = 0.050/0.00106052 = 47.176 kg

total mass in the tank = mass of steam + mass of water = 0.169350 + 47.176 = 47.316 kg