Determine the maximum force F that can be supported in the p

Determine the maximum force \"F\" that can be supported in the position shown if each chain can support a maximum tension of 600 lb before it fails.

Solution

sol:

Angle BAC = sin^-1(4/5 )= 53.13°
53.13° - 30° = 23.13°

For AC chain:
FCos 30° = 600 lb
F = 600/Cos 30° = 693 lb

For AB chain:
FCos 23.13° = 600 lb
F = 600/Cos 23.13° = 652 N

so maximum force F = 693 lb