1 How many grams of EDTA MW 29224gmol are needed to make a

1.) How many grams of EDTA (MW = 292.24g/mol ) are needed to make a 300mL of a 500mM solution? Show all of your work for full credit.

2.) How many mL of 1.5M Tris, pH8 are needed to make a 30mM Tris in a volume of 460mL? Show all of your work for full credit.

1. The formula to calculate the required molar concentration is:

Molarity= Molecular weight X Required concentration X Required volume

1000

Given: Molecular weight=292.24g/mol; Required concentration= 500mM (0.5M); Required volume= 300ml

Therefore,

No.of grams of EDTA required= 292.24 X 0.5 X 300 = 43.836 (g)

1000

2. The formula to determine concentration/volume is: C1VI=C2V2

Given: C1= 1.5M; C2= 30mM (0.03M); V2= 460ml;

Therefore initial voulme to be taken is V1= C2V2 = 0.03 x 460= 9.2 ml

C1 1.5