For each case below determine whether Q D E and C increase d

For each case below, determine whether Q, D, E,, and C increase, decrease, or remain the same relative to the initial situation. Justify each of the six answers. Initially, a parallel-plate capacitor with air between the plates is connected to a voltage source. The source remains connected. Finally, a dielectric is inserted between the plates. Initially, a parallel-plate capacitor with air between the plates is connected to a voltage source. Then the source is disconnected. Finally, a dielectric is inserted between the plates.

Solution

Where

Q=Charge on the capacitor

D=Distance between the plates

E=Electric field Between the plates

V=Potential difference across the capacitor

C=Capacitance of the capacitor

I DOnt Know the Sixth symbol.

a)

If a Dielectric is inserted ,With Voltage source remain connected.

1.So Potential difference V across the capacitor Remains the same.

2.Distance between the plates D ,has not changed ,so it Remains the same

3.Since Electric field E=V/D, so Electric field E Remains the same.

4.Since Capacitance is given by

C=Ke_oA/d

So capacitance increases by a factor of K

5.SO charge on the capacitor

Q=CV,

so it also increases by a factor of K

b)

Now here Voltage source is disconnected ,here charge Q remains the same

.1.Distance between the plates D ,has not changed ,so it Remains the same.

2.

.Since Capacitance is given by

C=Ke_oA/d

So capacitance increases by a factor of K.

3.Here Charge Q remains the same

4.Potentiall difference across the capacitor is

V=Q/C

So it Decreases by a factor K

5.

Since Electric field E=V/d

also decreases by a factor of `K