The uniform slender rod of mass m and length L is released f

The uniform slender rod of mass m and length L is released from rest in the inverted vertical position shown. Neglect friction and the mass of the small end roller and find the initial acceleration of A. Evaluate your result for theta = 20 degree, L = 465 mm, and m = 6.8 kg. The acceleration is positive if down the slope, negative if up the slope.

Solution

formula for calculating the angular accerleartions

a_A = (4g sin(q))/(cos²(q)+4sin²(q))

q = 20^o

a_A = (4x9.81 sin(20))/(cos²(20)+4sin²(20))

      = 9.9345m/sec²