fx x2x3 write fx as piece0wise defined function and find it

f(x) = (|x-2|)/(x+3)

write f(x) as piece0wise defined function and find its limits for x approaching 2 and x approaching -3 from right and left side of -3

also determine for what values of x is continuous and differentiable for f(x)

Solution

f(x)=(x-2)/(x+3) if x>=2
=(2-x)/(x+3) if x<=2

limx->2 f(x)=0

limx->-3-f(x)=-

limx->-3+f(x)=

f(x) = (|x-2|)/(x+3) write f(x) as piece0wise defined function and find its limits for x approaching 2 and x approaching -3 from right and left side of -3 also

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