fx x2x3 write fx as piece0wise defined function and find it
f(x) = (|x-2|)/(x+3)
write f(x) as piece0wise defined function and find its limits for x approaching 2 and x approaching -3 from right and left side of -3
also determine for what values of x is continuous and differentiable for f(x)
write f(x) as piece0wise defined function and find its limits for x approaching 2 and x approaching -3 from right and left side of -3
also determine for what values of x is continuous and differentiable for f(x)
Solution
f(x)=(x-2)/(x+3) if x>=2
=(2-x)/(x+3) if x<=2
limx->2 f(x)=0
limx->-3-f(x)=-
limx->-3+f(x)=
