Homework SourseThe velocity function in feet by second is given for a parti
The velocity function, in feet by second is given for a particle moving along a straight line. v(t) = t^2-t-90, 1< t<11 or 1=t=11 (a) Find the displacement (b)Find the total distance that the particle travels over the given interval
Solution
We know that
v=ds/dt
So,
ds/dt=t^2-t-90
Integrating above equation we get,
s=t3/3t2/290t+c
Substituting t as 1 and 11 and determining the resultant equations....
s(1)=90.1667+c
s(11)=606.8333+c ft
Subtracting these two, we get net displacement = -516.667ft
