Consider a diagram network using 32bit host address Suppose

Consider a diagram network using 32-bit host address. Suppose a router has four, numbered 0 through 3, and packets are to be forwarded to the link interfaces as follows: Destination Address Range Link Interface 11001000 00010111 00010000 00000000 through 0 11001000 00010111 00010111 11111111 11001000 00010111 00011000 00000000 through 1 11001000 00010111 00011000 11111111 11001000 00010111 00011100 00000000 through 2 11001000 00010111 00011111 11111111 otherwise 3 Provide a forwarding table that forwards packets to the correct link interfaces. Describe in detail how the forwarding table determine the appropriate link interface for datagram\'s with destination addresses: 200.23.30.18 200.23.20.18 200.18.1.30

Solution

a) Forwarding table forwards the packets and requires the minimum bits that are needed to convey enough information to route correctly.

Hence, Forwarding tables:

11001000 00010111 00010 -> Link inteface 0

11001000 00010111 00011000 -> Link interface 1

11001000 00010111 000111 -> Link interface 2

otherwise -> Link interface 3

b) 200 = 11001000

23 = 00010111

30 = 00011110

Therefore, 200.23.30.18 -> Link interface 2

200 = 11001000

23 = 00010111

20 = 00010100

Therefore, 200.23.20.18 -> Interface 0

200 = 11001000

18 = 00010010

Therefore, 200.18.1.30 -> Interface 3