Let V M2 Times 2 F be the vector space of 2 by 2 matrices a
     Let V = M2 Times 2 (F) be the vector space of 2 by 2 matrices, and consider a b the following sub spaces of V: U = {M =  and  Prove that if A, B  D  AB  D. (i.e. the product of two diagonal matrices is still diagonal).  Prove by induction on n  2 (using  too) that if A  D  (i.e. the powers of a diagonal matrix are still diagonal).  Prove that if L is a linear operator whose matrix A = AL is in D (i.e. is diagonal)  What you proved here is that for 2 by 2 diagonal matrices, we don\'t need to compute the 4-th power  we can stop at the 2-nd power!) 
  
  Solution
1) Product of 2 diagonal matrices is again a diagonal.
Hence AB belongs to D if A and B are diagonal matrices.
2) A^n is the product of n diagonal matrices A.
Hence again it is a diagonal matrix.
3) As diagonal matrix has 2 eigen values as in diagonal, eigen vectors will be (1,0) and (0,1)
hence MuL <=2

