0805 0568 0195 0043 0805 0568 0195 0043 The average age of r
0.805.
0.568.
0.195.
0.043.
| 0.805. | ||
| 0.568. | ||
| 0.195. | ||
| 0.043. |
Solution
So the probability is
P(xbar<68.5) = P((xbar-mean)/(s/vn) <(68.5-69)/(5.8/sqrt(100)) )
=P(Z<-0.86)
=0.1949 (from standard normal table)
Answer: 0.195
