Use part I of the Fundamental Theorem of Calculus to find th

Use part I of the Fundamental Theorem of Calculus to find the derivative of f (x) = 1 / 1 + t3 dt f\' (x) =

fundamental theorem:
if f(x)=₅^y(x) g(t)dt then

f^I(x) = y^I(x) * g(x) - (5)^I *g(x) ;

so substituting for given expression , we get ;

= 1* 1/1+x³ - 0 * 1/1+x³ ;

=1/1+x³

$Use part I of the Fundamental Theorem of Calculus to find the derivative of f (x) = 1 / 1 + t3 dt f\' (x) = Solutionfundamental theorem: if f(x)=5y(x) g(t)dt t$

Use part I of the Fundamental Theorem of Calculus to find th

Solution

Get Help Now

Submit a Take Down Notice