determine the upward force exerted on the cork by this mecha

Determine the upward force exerted on the cork by this mechanism. A log weighing 800 lb is lifted by a pair of tongs. Determine the forces exerted at E and

Solution

the vertical component of the force is F cos 15

Taking the lever now the moment generated about O is Fcos 15 x (31+66) = 75 cos15 x 97 = 7027.1 Nmm

This moment is opposed by the moment created by the cork forcs = 31 x F cork

therefore equating both we get Fcork = 7027.1/31 = 226.7 N which is 227 N