Quantum Mechanical Atom The orbital quantum number for the e

Quantum Mechanical Atom The orbital quantum number for the electron in a hydrogen atom is l = 6. What is the smallest possible value for the total energy of this electron?

According to my reference:

The orbital number L cannot be larger than n-1.

Therefore, if L = 6, n is at least as big as 7.

Since E_n = - 13.6 eV/(n^2), the total energy is at least

E_10 = - 13.6/49 = -0.277 eV