Standard penetration test SPT results in a granular soil dep

Standard penetration test (SPT) results in a granular soil deposit are summarized in Table below. Assume that 7- 18.5 kN/m and correct the SPT numbers using the Skempton\'s relationship (1986): . (i) What will be the net allowable bearing capacity of a foundation for a foundation 2m x 2m? Assume Dr 1.5 m. The allowable settlement 20 mm. (ii) Why do we use SPT method when there is a rigorous method such as the Meyerhof\'s general the bearing capacity method for the design of foundations? Field standard penetration number, N60 10 12 13 4 16 19

Solution

Let energy correction factor be Ce=o.8

and Pa=100KPa

Navg of the wholw strata=9.85 (we does not include value at 16m depth due to irregular variation)

From Fig. 13.5 Q = 10KPa for B = 2 m and Navg=9.85=10

safe bearing pressure = q=16xQ = 160 KPa

net safe bearing pressure = q - 18.5*1.5=131.95KPa

Advantage of SPT method over other rigorus method are:-

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Depth(m) Nfield Cn Overburden pressure(KPa) N160=Cn*Nfield*Ce
1 10 1,6875 18.5 13.5
4 12 1.15 74 11.04
7 13 0.87 129.5 9.048
11 11 0.66 203.5 5.808
16 19 0.505 296 7,676
 Standard penetration test (SPT) results in a granular soil deposit are summarized in Table below. Assume that 7- 18.5 kN/m and correct the SPT numbers using th

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