Standard penetration test SPT results in a granular soil dep
Standard penetration test (SPT) results in a granular soil deposit are summarized in Table below. Assume that 7- 18.5 kN/m and correct the SPT numbers using the Skempton\'s relationship (1986): . (i) What will be the net allowable bearing capacity of a foundation for a foundation 2m x 2m? Assume Dr 1.5 m. The allowable settlement 20 mm. (ii) Why do we use SPT method when there is a rigorous method such as the Meyerhof\'s general the bearing capacity method for the design of foundations? Field standard penetration number, N60 10 12 13 4 16 19
Solution
Let energy correction factor be Ce=o.8
and Pa=100KPa
Navg of the wholw strata=9.85 (we does not include value at 16m depth due to irregular variation)
From Fig. 13.5 Q = 10KPa for B = 2 m and Navg=9.85=10
safe bearing pressure = q=16xQ = 160 KPa
net safe bearing pressure = q - 18.5*1.5=131.95KPa
Advantage of SPT method over other rigorus method are:-
*Hope you like the solution*
| Depth(m) | Nfield | Cn | Overburden pressure(KPa) | N160=Cn*Nfield*Ce |
| 1 | 10 | 1,6875 | 18.5 | 13.5 |
| 4 | 12 | 1.15 | 74 | 11.04 |
| 7 | 13 | 0.87 | 129.5 | 9.048 |
| 11 | 11 | 0.66 | 203.5 | 5.808 |
| 16 | 19 | 0.505 | 296 | 7,676 |
