someone else answered before and were all incorrect Use the

someone else answered before and were all incorrect

Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers so that A_1 is smaller than A_2.) b = 26, c = 33, B = 21 degree A_1 = degree A_2 = degree C_1 = degree C_2 = degree a_1 = a_2 = Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Round your answers to one decimal place.) a = 54, b = 107, A = 50 degree B = degree C = degree c =

Solution

18) given b =26,c=33,B=21^o

by law of sines a/sinA=b/sinB=c/sinC

b/sinB=c/sinC

26/sin21^o=33/sinC

sinC=(33/26)sin21^o

C₁=27.1^o,C₂=152.9^o

A₁+B+C₁=180^o

A₁+21^o+27.1^o=180^o

A₁=131.9^o

A₂+B+C₂=180^o

A₂+21^o+152.9^o=180^o

A₂=6.1^o

a₁/sinA₁=b/sinB

a₁/sin131.9^o=26/sin21^o

a₁=26sin131.9^o/sin21^o

a₁=54

a₂/sinA₂=b/sinB

a₂/sin6.1^o=26/sin21^o

a₂=26sin6.1^o/sin21^o

a₂=7.7

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