Find z such that 967 of the standard normal curve lies to th

Find z such that 96.7% of the standard normal curve lies to the left of z. (Round your answer to two decimal places.) z =

Normal Distribution
Mean ( u ) =0
Standard Deviation ( sd )=1
Normal Distribution = Z= X- u / sd ~ N(0,1)
P ( Z < x ) = 0.967
Value of z to the cumulative probability of 0.967 from normal table is 1.838
P( x-u/s.d < x - 0/1 ) = 0.967
That is, ( x - 0/1 ) = 1.84
--> x = 1.84 * 1 + 0 = 1.838