enthalpy in book for h1 is 4010 kjkg NG 2000 Themod mamics a

enthalpy in book for h1 is 401.0 kj/kg

NG 2000 Themod mamics at005 )Saturated liqud prorsn at 0 bar poes trosgh a throtling prosess. It exits the poe the throttling device 115 poia Pr 05 ber t:O : Q:w.pe: -o steudy stals

Solution

The problem is called Throttling process.

h 1 =401 kJ/kg

p1=40 bar

p2 =0.05 bar

By first law of thermo: W = mP1V1- mP2V2

also U-W=Q

but Q=0 by condition

So U=W

DU = CvDT = P2V2 - P1V1, if V is same

then CvDT = VDp

USE Tables to get Cv and specific volume, knowing DP as 40-.05 = 39.95 bar