If someone can answer A correctly then I can post B and C in

If someone can answer A correctly, then I can post B and C in comment for full points ^^^

(a) Given a=0.04, Z(0.02) =2.05 (from standard normal table)

So n=(Z/E)^2*p*(1-p)

=(2.05/0.04)^2*0.52*(1-0.52)

=655.59

Take n=656

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(a) Given a=0.01, Z(0.005) = 2.58 (from standard normal table)

So n=(Z/E)^2*p*(1-p)

=(2.58/0.03)^2*0.24*(1-0.24)

=1349.03

Take n=1350

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(b) We use p=0.5 as estimated.

So n=(Z/E)^2*p*(1-p)

=(2.58/0.03)^2*0.5*(1-0.5)

=1849