Find the x and y intercepts if any exist x 22 y2 9Solutio

Find the x and y intercepts if any exist.

(x + 2)² + y² = 9

for x intercepts , y =0

(x + 2)² + 0² = 9

(x + 2)² = 9

(x + 2)= -9,(x + 2)= 9

(x + 2)= -3,(x + 2)= 3

x=-5,x=1

x intercepts are (x,y)= (-5,0),(1,0)

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(x + 2)² + y² = 9

for y intercepts , x =0

(0 + 2)² + y² = 9

4+y² = 9

y² = 5

y =-5, y=5

y intercepts are (x,y)= (0,-5),(0,5)