From the above information calculate the Keq and delta G for

From the above information, calculate the K\'_eq and delta G for the overall reaction shown below the line, T = 37 degree C. Use your data from the previous question to calculate the delta G given the cellular concentrations of reactants and products below.

Solution

Del G^o\' (overall) = 13.91 + 25.12 - 28.40 - 41.45 - 0.003

Del G^o\' (overall) = - 30.823 kJ/mol

Del G = -RT ln Keq

Keq = e^{-Del G/RT}

R = 8314 KJ/mol .K, T = 37 + 273 = 310 K

Keq = e^{- (-30.823/8314 x 310)}

Keq = 1

b) Del G = - RT ln Keq

Keq = [products] / [reactants]

[Pyruvate][pyruvate][phosphoenolpyruvate][NADH][ATP][GTP][ADP][GDP][CO2][CO2][H2O][H+][HCO3] K eq = divided by

[Oxaloacetate] [Oxaloacetate][Lactate][ATP][ADP][GTP][GDP][Pi][H+][H+][NAD+][HCO3]

After subst. all the values, Keq = 455.72 x 10 ³

Del G = - 8314 x 310 x ln (455.72 x 10 ³)

= - 33.57 x 10 ³ KJ/mol