Design a class named Location for locating a maximal value a
Solution
LocationTest.java
import java.util.Scanner;
public class LocationTest {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.print(\"Enter the number of rows and columns in the array: \");
int rows = scan.nextInt();
int cols = scan.nextInt();
double d[][] = new double[rows][cols];
System.out.println(\"Enter the array: \");
for(int i=0; i<d.length; i++){
for(int j=0; j<d[i].length; j++){
d[i][j] = scan.nextDouble();
}
}
Location l = locateLargest(d);
System.out.println(\"The location of the largest element is \"+l.maxValue+\" at (\"+l.row+\", \"+l.column+\")\");
}
public static Location locateLargest(double[][] a){
double max = a[0][0];
int row =0 , col=0;
for(int i=0; i<a.length; i++){
for(int j=0; j<a[i].length; j++){
if(max<a[i][j]){
max = a[i][j];
row = i;
col = j;
}
}
}
Location l = new Location(row,col,max);
return l;
}
}
Location.java
public class Location {
public int row,column;
public double maxValue;
public Location(int row, int column, double maxValue){
this.row = row;
this.column =column;
this.maxValue = maxValue;
}
}
Output:
Enter the number of rows and columns in the array: 3 4
Enter the array:
23.5 35 2 10
4.5 3 45 3.5
35 44 5.5 9.6
The location of the largest element is 45.0 at (1, 2)

