The roots for x3 x2 36x 36 are a 6 b 1 c 61 d 4 2 e none

The roots for x^3 - x^2 - 36x +36 are:   a. ± 6    b. ±1   c. ±6,1    d. ±4, ±2     e. none of these

Solution

x^3 -x^2 -36x +36 =0

we can see x=1 is one root : 1-1-36+36=0

now divide :(x^3 -x^2 -36x +36)/(x- 1)

=x^2(x-1)/(x-1) -36(x-1)/(x-1)

=x^2 -36

Roots of x^2 -36 =0; x = +/-6

So, roots are x = 1 , -6 , 6

Option C