I do not understand how to put the answer in the form of fra

I do not understand how to put the answer in the form of fraction.

A clinic took temperature readings of 250 flu patients over a weekend and discovered the temperature distribution to be Gaussian, with a mean of 101.70°F and a standard deviation of 0.5630. Use this normal error curve area table to find the following values. (a) What is the fraction of patients expected to have a fever greater than 103.39°F?

(b) What is the fraction of patients expected to have a temperature between 101.59°F and 102.21°F?

Ordinate and Area for a Normal Error Curve

z = (x – )/
The area refers to the area between z = 0 and z = the table value.

Solution

a)

We first get the z score for the critical value. As z = (x - u) / s, then as          
          
x = critical value =    103.39      
u = mean =    101.7      
          
s = standard deviation =    0.563      
          
Thus,          
          
z = (x - u) / s =    3.001776199      
          
Thus, using a table/technology, the right tailed area of this is          
          
P(z >   3.001776199   ) =    0.001342047 [answer]

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b)

We first get the z score for the two values. As z = (x - u) / s, then as          
x1 = lower bound =    101.59      
x2 = upper bound =    102.21      
u = mean =    101.7      
          
s = standard deviation =    0.563      
          
Thus, the two z scores are          
          
z1 = lower z score = (x1 - u)/s =    -0.195381883      
z2 = upper z score = (x2 - u) / s =    0.905861456      
          
Using table/technology, the left tailed areas between these z scores is          
          
          
P(z < z2) =    0.817495406      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.817495406   [answer]