Given Hx3rad2x312 Write Hx as the composition of 3 simpler f

Given H(x)=3(rad2x^3+1)-2. Write H(x) as the composition of 3 simpler functions such that H(X)=f(g(k(x))), where none of the simpler functions are the identity fuction.

Solution

H(x)=3(rad2x^3+1)-2.

such that H(X)=f(g(k(x)))

Now from given composite function H(x) = 3(x) -2

Now x in H(x) is g(k(x))

k(x) can be = 2x^3

and g(x) = rad(x) +1

So, we have : H(x) =3x -2

k(x) = 2x^3

g(x) = rad(x) +1