| The candy company that makes M&M\'s claims that 10% of the M&M\'s it produces is green. Suppose that the candies are packaged at random in large bags of 200 M&M\'s. When we randomly pick a bag of M&M\'s, we may assume that this represents a simple random sample of size n = 200. Suppose we wish to test H0: p = 0.10 versus Ha: p 0.10. Suppose that in the randomly selected bag of M&M\'s there are only 12 green M&M\'s. Calculate the value of the large-sample z statistic. What is the value of the corresponding P-value? |
| | | A)P-value = 0.06 | | | B)P-value = 0.0593 | | | C)P-value = 0.0297 | | | D)P-value = 0.3284 | | |
| The candy company that makes M&M\'s claims that 10% of the M&M\'s it produces is green. Suppose that the candies are packaged at random in large bags of 200 M&M\'s. When we randomly pick a bag of M&M\'s, we may assume that this represents a simple random sample of size n = 200. Suppose we wish to test H0: p = 0.10 versus Ha: p 0.10. Suppose that in the randomly selected bag of M&M\'s there are only 12 green M&M\'s. Calculate the value of the large-sample z statistic. What is the value of the corresponding P-value? |
| | | A)P-value = 0.06 | | | B)P-value = 0.0593 | | | C)P-value = 0.0297 | | | D)P-value = 0.3284 | | |
Set Up Hypothesis
Null, H0:P=0.1
Alternate, H1: P!=0.1
Test Statistic
No. Of Success chances Observed (x)=12
Number of objects in a sample provided(n)=200
No. Of Success Rate ( P )= x/n = 0.06
Success Probability ( Po )=0.1
Failure Probability ( Qo) = 0.9
we use Test Statistic (Z) for Single Proportion = P-Po/Sqrt(PoQo/n)
Zo=0.06-0.1/(Sqrt(0.09)/200)
Zo =-1.8856
P-Value: Two Tailed ( double the one tail ) - Ha : ( P != -1.88562 ) = 0.0593
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